Non linear

Nonlinear Pharmacokinetics

Non linear pharmacokinetics:
In some cases, the kinetics of a pharmacokinetic process change from predominantly first order to predominantly zero order with increasing dose or chronic medication. A mixture of both first order and zero order kinetics is called as mixed order kinetics. Also known as nonlinear kinetics or dose dependent kinetics. Eg. vitamin C, naproxen, riboflavin. The kinetics of such capacity limited processes can be described by the Michaelis-Menten kinetics.

Linear Pharmacokinetics

Non Linear Pharmacokinetics
Pharmacokinetic parameters for a drug would not change with change in dose
Pharmacokinetic parameters for a drug can change with change in dose.
Dose Independent
Dose dependent
First Order kinetics
Also called as Mixed order, Saturated kinetics, capacity limited
All semilog plots of C vs t for diff. doses are superimposable.
Not superimposable

Examples of Drugs Showing Nonlinear Kinetics

Drug

Absorption is carrier mediated.

Riboflavin, gebapentin, L-dopa, baclofen, ceftibuten
Drugs with low solubility in GI but relatively high dose
Chorothiazide, griseofulvin, danazol
Presystemic hepatic metabolism attains saturation
Propranolol

Saturable plasma protein binding

Phenylbutazone, lidocaine, salicylic acid, ceftriaxone, diazoxide, phenytoin, warfarin, disopyramide
Cellular uptake
Methicillin (rabbit)
Tissue binding
Imiprimine (rat)
Saturable transport into or out of tissues
Methotrexate

Active secretion

Mezlocillin, para-aminohippuric acid
Tubular reabsorption
Riboflavin, ascorbic acid, cephapirin
Change in urine pH
Salicylic acid, dextroamphetamine

Saturable metabolism

Cofactor or enzyme limitation
Acetaminophen, alcohol
Enzyme induction
Carbamazepine
Altered hepatic blood flow
Propranolol, verapamil
Metabolite inhibition
Diazepam

Biliary secretion

Iodipamide, sulfobromophthalein sodium
Enterohepatic recycling
Cimetidine, isotretinoin

Drugs that demonstrate saturation kinetics usually show the following characteristics:

Elimination of drug does not follow simple first-order kinetics—that is, elimination kinetics are nonlinear. 2. The elimination half-life changes as dose is increased. Usually, the elimination half-life increases with increased dose due to saturation of an enzyme system. However, the elimination half-life might decrease due to "self"-induction of liver biotransformation enzymes, as is observed for carbamazepine.

3. The area under the curve (AUC) is not proportional to the amount of bioavailable drug. 4. The saturation of capacity-limited processes may be affected by other drugs that require the same enzyme or carrier-mediated system (ie, competition effects). 5. The composition and/or ratio of the metabolites of a drug may be affected by a change in the dose.


large dose curve is obtained with an initial slow elimination phase followed by a much more rapid elimination at lower blood concentrations (curve A). small dose apparent first-order kinetics are observed, because no saturation kinetics occur (curve B). If the pharmacokinetic data were estimated only from the blood levels described by curve B, then a twofold increase in the dose would give the blood profile presented in (curve C), which considerably underestimates the drug concentration as well as the duration of action.

Curve A = Saturated kineticsCurve C = Dose Independent KineticsA plot of the areas under the plasma level–time curves at various doses should be linear.

Saturable Enzymatic Elimination Processes

Michaelis–Menten kinetics:dCp/dt = rate of decline of drug concentration with time,Vmax = theoretical maximum rate of the process,Km = Michaelis constant, reflects the capacity of the enzyme system , equal to the drug concentration or amount of drug in the body at 0.5V max.

C p >> K m

C p = K m
C p << K m
saturation of the enzymes occurs. The value for K M is negligible. The rate of elimination proceeds at a constant rate

Rate of process is = one half of its max. rate -dc/dt = Vmax/2

rate of drug elimination becomes a first-order process

Conc. (g/ml)

Elimination rate (g/mL per hr) Calculated from equation 1
0.4
0.400
0.8
0.444
1.2
0.462
1.6
0.472
2.0
0.476
2.4
0.480
2.8
0.483
3.2
0.485
10.0
0.495
10.4
0.495
10.8
0.495
11.2
0.496
11.6
0.496



Problem: from above data Using the hypothetical drug considered in (V max = 0.5 g/mL per hour, K M = 0.1 g/mL), how long would it take for the plasma drug concentration to decrease from 20 to 12 g/mL? Solution Because 12 g/mL is above the saturable level, as indicated in , elimination occurs at a zero-order rate of approximately 0.5 g/mL per hour. 0.5 g/ml 1 Hr 8 g/ml 16Hr

First order Rate constant =V max/KM = 1.1 Hr -1 From this we can find out Half Life

Elimination Rate (g/mL per hr)
Elimination Rate Constant (hr– 1) 0.01
0.011
1.1
0.02
0.022
1.1
0.03
0.033
1.1
0.04
0.043
1.1
0.05
0.053
1.1
0.06
0.063
1.0
0.07
0.072
1.0
0.08
0.082
1.0
0.09
0.091
1.0
K M = 0.8
g/mL, V max = 0.9


Drug Elimination by Capacity-Limited Pharmacokinetics: One-Compartment Model, IV Bolus Injection
If a single IV bolus injection of drug (D 0) is given at t = 0, the drug concentration (C p) in the plasma at any time t may be calculated by an integrating equation,

Amount of drug in the body after IV Bolus ,

Where, D 0 is the amount of drug in the body at t = 0. Rearranging equation:

Amount of drug (mg) Vs Time (hr) at diff. velocity and Constant Km Velocity Inversely Proportional to Time
The relationship of K M and V max to the time

Amount of drug (mg) Vs Time (hr) at diff. KM and Constant Vmax Km is directly proportional to Time. As Km is incereases, time required to decline the drug also increases


Practice:A drug eliminated from the body by capacity-limited pharmacokinetics K M of 100 mg/L and a V max of 50 mg/hr. If 400 mg of the drug is given to a patient by IV bolus injection calculate the time for the drug to be 50% eliminated. If 320 mg of the drug is to be given by IV bolus injection, calculate the time for 50% of the dose to be eliminated.

small changes in the dose will produce large differences in the time for 50% drug elimination. Because of Saturation

the amount of drug in the body is well below saturation of the elimination process and the drug declines at a first-order rate.

Determination of K M and V max

C (
V (
1/V (mL per min/
1/C (mL/
Observation Number


1/v
1/c
1
1
0.500
2.000
1.000
2
6
1.636
0.611
0.166
3
11
2.062
0.484
0.090
4
16
2.285
0.437
0.062
5
21
2.423
0.412
0.047
6
26
2.516
0.397
0.038
7
31
2.583
0.337
0.032
8
36
2.504
0.379
0.027
9
41
2.673
0.373
0.024
10
46
2.705
0.369
0.021

1) Lineweaver–Burke plot:

y-intercept =1/V max the slope = K M/V max.

Disadvantage: The points are clustered.

2) Plot of C/v versus C

Yield a straight line slope = 1/V max Intercept = K M/V max

3) Plot of v Vs v/C
slope = –K M intercept = V max

4) From steady state plasm drug concentration:

At steady state the rate of drug metabolism (v) = rate of drug input R (dose/day). Inverting above equation:

A plot of R versus C SS is plotted

Mark points for R of 300 mg/day and C SS of 25.1 mg/L as shown. Connect with a straight line. Mark points for R of 150 mg/day and C SS of 8.6 mg/L as shown. Connect with a straight line. Where lines from the first two steps cross is called point A. From point A, read V max on the y axis and K M on the x axis.

5) Direct Method

Used when only two dose levels


Combining Two Equations:


C 1 is steady-state plasma drug concentration after dose 1, C 2 is steady-state plasma drug concentration after dose 2, R 1 is the first dosing rate, R 2 is the second dosing rate.

Interpretation of K M and V max

An understanding of Michaelis–Menten kinetics provides insight into the nonlinear kinetics and helps to avoid dosing a drug at a concentration near enzyme saturation.Eg. Conc. = 8.6mg/L Km =27.3 mg/L dose = 300mg/day V max = 626 mg/day50% V max, ie, 0.5 x 626 mg/day or 313 mg/day. subject is receiving 300 mg of phenytoin per day, theplasma drug concentration of phenytoin is 8.6 mg/L, which is considerably below the K M of 27.3 mg/L

Diagram showing the rate of metabolism when V max is constant (8 g/mL/hr) K M is changed -K M = 2 g/mL for top curve -K M = 4 g/mL for bottom curve Note the rate of metabolism is faster for the lower K M, but saturation starts at lower concentration.

Zero-Order Input and Nonlinear Elimination The usual example of zero-order input is constant IV infusion. If the drug is given by constant IV infusion and is eliminated only by nonlinear pharmacokinetics, then the following equation describes the rate of change of the plasma drug concentration:
Non- linear Elimination
Zero-Order Input

First-Order Absorption and Nonlinear Elimination

input extravascularly (eg, orally), absorbed by first-order absorption Eliminated only by nonlinear pharmacokinetics :

k a is the first-order absorption rate constant

Nonlinear Elimination
First-Order Absorption